A coaxial cable consists of a 1.2-mm-diameter inner conductor and a 0.20-mm-thic
ID: 1339906 • Letter: A
Question
A coaxial cable consists of a 1.2-mm-diameter inner conductor and a 0.20-mm-thick outer conductor with interior diameter 1.2cm. A 100-mA current flows down the inner conductor and back along the outer conductor. Find the magnetic field strength:a) 0.10 mm from the cable axis
T
b) 5.0 mm from the cable axis
T
c) 2.0 cm from the cable axis
T A coaxial cable consists of a 1.2-mm-diameter inner conductor and a 0.20-mm-thick outer conductor with interior diameter 1.2cm. A 100-mA current flows down the inner conductor and back along the outer conductor. Find the magnetic field strength:
a) 0.10 mm from the cable axis
T
b) 5.0 mm from the cable axis
T
c) 2.0 cm from the cable axis
T
Explanation / Answer
a)
d = 0.1 mm lies in inner conductor
B= miuo*Ienclosed/ (2*pi*d)
I enclosed = 0.1 A*pi*d^2 / (pi*r1^2)
I enclosed = 0.1 A*d^2 / (r1^2)
= 0.1*(0.1)^2 / (0.6)^2
=2.78*10^-3 A
B= miuo*Ienclosed/ (2*pi*d)
= (1.2566*10^-6)*(2.78*10^-3) / (2*pi*0.1*10^-3)
=5.56*10^-6 T
b)
d = 5 mm lies between inner and outer conductor
Here I enclosed = 0.1 A
B= miuo*Ienclosed/ (2*pi*d)
= (1.2566*10^-6)*(0.1) / (2*pi*5*10^-3)
=4*10^-6 T
c)
d =2 cm lies outside outer conductor.
I enclosed = 0
Bceuase current flowing down equals current flowing up
B = 0 T
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