Voltage is observed to decrease to 80% of the value in part (a). What is the val
ID: 1338762 • Letter: V
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17) The peak voltage is the maximum voltage given by this function. Max. value of sin function is 1. Hence peak voltage is given by Vp= 5V.
a) average voltage = (2/pi)Vp = 0.637* 5V = 3.185V
b) peak voltage, Vp= 5V
c) peak to peak voltage = 2Vp= 2*5V = 10V
d) rms voltage = (1/sqrt(2))Vp = 0.707*5V = 3.535V
e) Frequency, f = w/2pi = where w is the angular frequency measured in radians/sec
Here 0.0628 is the angular frequency.
therefore, f = 0.0628/2*3.14 = 0.01sec-1
f) Time period, T = 2pi/w
Hence, T = 2*3.14/0.0628 = 100 seconds
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