A 1500 kg sedan goes through a wide intersection traveling from north to south w

Question

A 1500 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2200 kg SUV traveling from east to west. The two cars become enmeshed due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.75, and the cars slide to a halt at a point 5.36 m west and 6.37 m south of the impact point.

How fast was sedan traveling just before the collision?

How fast was SUV traveling just before the collision?

Explanation / Answer

let the speed of sedan is u1

speed of SUV is u2

for the speed after collision in south

vs^2 = 2 * 0.75 * 9.8 * 5.36

vs = 8.88 m/s

for the speed after collsion in west

ve^2 = 2 * 0.75 * 9.8 * 6.37

ve = 9.68 m/s

Now , for the speed of sedan , using conseravtion of momentum in south direction

(1500 + 2200) * 8.88 = 1500 * u1

u1 = 21.9 m/s

the speed of Sedan before collision is 21.9 m/s

for the conservation of momentum in east direction

(1500+ 2200) * 9.68 = v2 * 2200

v2 = 16.3 m/s

the speed of SUV before collision is 16.3 m/s

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