Exercise Colmision between Onequal Mass Balls This last part is similar to the p

Question

Exercise Colmision between Onequal Mass Balls This last part is similar to the previous section except a plastic ball is used as the target. The mass of plastic ball is significantly less than the mass of the steel ball. Question: What happens if the plastic bal is used as the projectile and the steel ball as the target? We first consider the case where the steel ball collides head on with the plastic ball. We assume that the collision is elastic, i.e., the initial and final kinetic energies are equal. In this case we have two equations Conservation of momentum: + rt steelv steel + ml plasticV plastic-msteelV plastic plastic Conservation of energy: 2steel steel2"plastic plastic v2 Plastic = jmsteelvsteel + 2 mplastic plastic where the prime represents the final velocities. These two equations simplify to plastic stee plastic steel Note that the initial speed of the plastic, Vplastic - 0. In part I, you found that the speed and momentum of the steel ball at the bottom of the ramp are 1.61 m/s and siet V steel0.0446 kg-m/s respectively. By substituting Equation [9] into [7], the speeds of the steel and plastic balls after the collision can be determined. Simplifying gives Vplastic = mete-n,late [10] The speed of the steel ball after collision is then steel te plastic What is the speed of plastic ball after collision? Use Equation [10] to calculate the speed of the plastic ball. The mass of the steel ball is 27.7 g and that of the plastic ball is 12.7 g 2.21 m/s You are correct. Computer's answer now shown above Your receipt no. is 157-9563 (2) VI What is the speed of steel ball after collision? Use Equation [11] to calculate the speed of the steel ball 0.598 m/s You are correct. Computer's answer now shown above Your receipt no. is 157-8574 VI Now since we also know the time it takes for the steel and plastic balls to fall to the floor, we can calculate the horizontal distance traveled by each ball. The time taken to fall is determined earlier to be 0.2329 s. What is the horizontal distance traveled by the plastic ball after collision? Note the units for the distances. 950 cm Submit Answer Incorrect. Tries 1/10 Previous Tries js

Explanation / Answer

Speed of Plastic Ball after Collision, = 2.1 m/s
Time taken to Fall = 0.2329 s

Distance travelled = 2.1 * 0.2329 m
Distance travelled = 2.1 * 0.2329 * 100 cm
Distance travelled by Plastic ball = 48.9 cm

Speed of Plastic Ball after Collision, = 0.598 m/s
Time taken to Fall = 0.2329 s

Distance travelled = 0.598 * 0.2329 m
Distance travelled = 0.1393 * 100 cm
Distance travelled by Steel ball = 13.93 cm

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.