A box is given a push so that it slides across the floor. How far will it go, gi

Question

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.12 and the push imparts an initial speed of 3.6 m/s? A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.12 and the push imparts an initial speed of 3.6 m/s? A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.12 and the push imparts an initial speed of 3.6 m/s?

Explanation / Answer

Fn = mg; Ff = µmg; a = F/m = Ff/m = µmg/m = µ*g
So, the box will decelerate with a = -µ*g = -.0.12*9.8 = -1.176 m/s².
Knowing the initial V and a,

x = V²/2a = (3.6)²/(2x1.176) = 5.5 m

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