Now let’s consider an example based on Henry Cavendish’s famous experiment to di

Q: Now let’s consider an example based on Henry Cavendish’s famous experiment to di

Fg = G M m / r2 = 6.67 * 10-11 * 0.01 * 0.5 / [0.05]2 = 1.33 * 10-10 N If the distance is doubled, the force would reduce 4 times, so new force would be- Fg' = 1.33 * 10-10 / 4 = 3.325 * 10-11 N

ID: 1335961 • Letter: N

Question

Now let’s consider an example based on Henry Cavendish’s famous experiment to directly measure the gravitational force between two spheres. Suppose that the mass m1 of one of the small spheres of a Cavendish balance is 10.0 g (=0.0100kg), the mass m2 of one of the large spheres is 0.500 kg, and the center-to-center distance between each large sphere and the nearer small one is 0.0500 m. Find the magnitude of the gravitational force Fg on each sphere due to the nearest other sphere.

What is the force magnitude Fg if the separation between the centers of the spheres is doubled to 0.100 m ?

Explanation / Answer

Fg = G M m / r2

= 6.67 * 10-11 * 0.01 * 0.5 / [0.05]2 = 1.33 * 10-10 N

If the distance is doubled, the force would reduce 4 times, so new force would be-

Fg' = 1.33 * 10-10 / 4 = 3.325 * 10-11 N

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Now let’s consider a projectile problem in which the initial velocity is specifi

Now let’s consider an example based on Henry Cavendish’s famous experiment to di

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Now let’s consider an example based on Henry Cavendish’s famous experiment to di

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