Three resistors having resistances of R 1 = 1.55 , R 2 = 2.54 , and R 3 = 4.91 r

Question

Three resistors having resistances of R1 = 1.55 , R2 = 2.54 , and R3 = 4.91 respectively, are connected in parallel to a 27.9 V battery that has negligible internal resistance.

Part A

Find the equivalent resistance of the combination.

Part B

Find the current in each resistor.

Answer in the order indicated. Separate your answers using commas.

Part C

Find the total current through the battery.

Part D

Find the voltage across each resistor.

Answer in the order indicated. Separate your answers using commas.

Part E

Find the power dissipated in each resistor.

Answer in the order indicated. Separate your answers using commas.

Part F

Which resistor dissipates the most power, the one with the greatest resistance or the one with the least resistance? Explain why this should be.

Explanation / Answer

1/Rnet = (1/1.55)+(1/2.54)+(1/4.91)

Rnet = 0.804 ohm

B) I1 = V/R1 = 27.9/1.55 = 18 A

I2 = V/R2 = 27.9/2.54 = 10.98 A

I3 = V/R3 = 27.9/4.91 = 5.68 A

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C) I = I1+I2+I3 = 18+10.98+5.68 = 34.66 A

D) V1 = V2 = V3 = 27.9 V

E) P1 = V1^2/R1 = 27.9^2/1.55 = 502.2 W

P2 = V2^2/R2 = 27.9^2/2.54 = 306.46 W

P3 = V3^2/R3 = 27.9^2/4.91 = 158.53 W

least resisatnce dissipates more power

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