A mass m = 0.016 kg is attached to a horizontal spring with constant k = 19.0 N/

Question

A mass m = 0.016 kg is attached to a horizontal spring with constant k = 19.0 N/m. Friction and the mass of the spring itself are negligible. At time t = 0, the mass is observed to be displaced 45.0 mm to the right of its equilibrium position, and to be moving to the right at 1.616 m/s. The motion is described by x = xmcos(t + ), with the +x direction to the right.

a. What is the value of xm?

b. What is the value of the phase constant ? Enter an angle between - rad and + rad.

c. What is the total energy in the oscillation of the spring and mass system?

Explanation / Answer

he value of xm is 45.0 mm

The phase constant is pi/2

The total enrgy is

0.5kA2=0.5(19)(0.045)2=0.0192375 J

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