A football coach starts at the 10-yard line (A) and walks to the 40-yard line (B

Question

A football coach starts at the 10-yard line (A) and walks to the 40-yard line (B) in 3 minutes. He turns around and walks to the 0-yard line (C) in the next 2 minutes. He turns around again and walks back to the 50 -yard line (D) in the next three minutes. He turns around once more and walks back to the 25-yard line (E) in the next two minutes, thus completing his 10 minutes of pacing. The coach's overall displacement is 15 yd, east 15 yd, west 15 yd 50 yd, east 50 yd, west 50 yd 60 yd, east 60 yd, west 60 yd 85 yd, east 85 yd, west 85 yd 145 yd, east 145 yd, west 145 yd none of these

Explanation / Answer

Let us take the initial position be

x = 10yd line <------- at t= 0s

After the 10 mins,

the final position is 25 yd line

So, overall displacement = 25-10 = 15 yd towards east

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