A 60.0 kg woman slides down a waterslide with a height of 21.9 m. a.) Determine

Question

A 60.0 kg woman slides down a waterslide with a height of 21.9 m. a.) Determine the speed of the woman as she reaches the bottom if the slides is frictionless b.) If the woman is clocked at 18.0 m/s at the bottom of the slide, find the work done on the woman by friction. A 60.0 kg woman slides down a waterslide with a height of 21.9 m. a.) Determine the speed of the woman as she reaches the bottom if the slides is frictionless b.) If the woman is clocked at 18.0 m/s at the bottom of the slide, find the work done on the woman by friction. A 60.0 kg woman slides down a waterslide with a height of 21.9 m. a.) Determine the speed of the woman as she reaches the bottom if the slides is frictionless b.) If the woman is clocked at 18.0 m/s at the bottom of the slide, find the work done on the woman by friction.

Explanation / Answer

a) Apply energy conservation,

final kinetic energy = initial potential energy

0.5*m*v^2 = m*g*h

==> v = sqrt(2*g*h)

= sqrt(2*9.8*21.9)

= 20.72 m/s

b) Workdone by friction = change in mechaincal energy

= final mechanical energy - initail mechanical energy

= 0.5*m*v^2 - m*g*h

= 0.5*60*18^2 - 60*9.8*21.9

= -3157.2 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.