Suppose that the curved portion of the Gaussian surface in part a is replaced by

Question

Suppose that the curved portion of the Gaussian surface in part a is replaced by the larger curved surface as shown. The flat left-hand portion of the surface is unchanged. Does the value of L change? Explain. How does the flux through the new curved portion of the surface compare to the flux through the original curved portion of the surface? Explain. Suppose that the curved portion of the Gaussian surface is replaced by the larger curved surface that encloses the charge as shown. The flat left-hand portion of the surface is still unchanged. Does the value of change? Explain. How does the flux through the new curved portion of the surface compare to the flux through the original curved portion of the surface? Explain Use Gauss' law to write an expression in terms of L and q for the flux through the curved portion of the surface.

Explanation / Answer

i) flux = 0
because from gauss law
flux through a closed surface = charge enclosed by the surface/

here , charge enclosed =0

hence flux = 0

ii) fom part (i)

we know that,

total flux = 0

L + c = 0

c = -L

(iii) L does not change because the left surface has not changed.

flux through this new surface , c_new must satisfy

c_new + L =0 ( from gauss law)

c_new =- L

hence, it remains the same

(iv)

L will remain same, because the left hand portion of surface is unchanged with respect to q

however,

from gauss law

c + L =q/ (beacuse the surface now encloses q)

c = q/ - L

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