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2. How much heat in joules is needed to raise the temperature of 1.5 L of water

ID: 1331887 • Letter: 2

Question

2. How much heat in joules is needed to raise the temperature of 1.5 L of water from 0°C to 71.0°C? (Hint: Recall the original definition of the liter.)

______ J

3. A cylinder of gas is at room temperature (20°C). The air conditioner breaks down, and the temperature rises to 64°C. What is the new pressure of the gas relative to its initial pressure (p1)?

4. A cylinder of gas at room temperature (20°C) has a pressure p1. To what temperature in degrees Celsius would the temperature have to be increased for the pressure to be 2.2p1?

______ °C

5. A quantity of gas in a piston cylinder has a volume of 0.409 m3 and a pressure of 200 Pa. The piston compresses the gas to 0.229 m3 in an isothermal (constant-temperature) process. What is the final pressure of the gas?

______ Pa

6. A quantity of gas in a piston cylinder has a volume of 0.453 m3. If the gas is initially at room temperature (20°C) and is heated in an isobaric (constant-pressure) process, then what will be the temperature of the gas in degrees Celsius when it has expanded to a volume of 0.802 m3?

______°C

Consider the figure below. r= 1 m r=2m r= 3 m Indicate over how many squares the sound waves would spread for r = 7 m squares The sound intensity would decrease to what fraction in value?

Explanation / Answer

multiple questions I am allowed to solve 1 question at a time.

question 2)

One calorie = the amount of heat needed to raise the temperature of 1.0 milliliter of water by one Celcius degree. So:

1.5 liters = 1500 milliliters
71°C - 0°C = 71 Celcius degrees

71 * 1500 = 106500 calories

or

Also the energy to raise 1 kg of water by 1 Celius equals 4.18 kJ. (In other words, the specific heat of water is c = 4.18 kJ/(kg C)

So

Q = m * c *T
= 1.5 kg * 4.18 kJ/(kg C) * (71.0 C - 0 C) = 4.45 10³ kJ

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