A uniform electric field of magnitude 229 V/m is directed in the positive x dire

Question

A uniform electric field of magnitude 229 V/m is directed in the positive x direction. A + 11.5 uC charge moves from the origin to the point (x, y) = (19.0cm, 51.7 cm). What was the change in the potential energy of this charge? (in J) -5.38 times 10-5 -7.81 times 10-5 -1.13 times 10-4 -1.64 times 10-4 -2.38 times 10-4 -3.45 times 10-4 -5.00 times 10-4 -7.26 times 10-4 Through what potential difference did the charge move? (in V) -4.35 times 10 -5.09 times 101 -5.96 times 101 -6.97 times 101 -8.15 times 101 -9.54 times 101 -1.12 times 102 -1.31 times 102

Explanation / Answer

PE = -qEdcostheta

PE = -qE*.19cos0 -qE *.517cos90

PE = -qE *.19

PE = 11.5 x 10^-6 x 229 x .19

PE = -5.00 x 10^-4 J ( G option )

part b )

dw = E*dcostheta

dw = 229 * .19

dw = 4.35 x 10^1 V ( A option )

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