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The https:// www.theexpertta.com /Common/TakeTutorialAssignment.aspx facebook YouTube Home I Stude joshuaquansah@rocketmail.com My Account Log Out Class Management I Help Homework 4 Begin Date: 9/10/2015 5:00:00 PM Due Date: 10/2/2015 5:00:00 PM End Date: 0/9/2015 5:00:00 PM Prob 7: A bt deq g by play g pushed backward by g play rting a fo pp 880 N on him. The mass of the losing player plus equipment is 84 kg, and he is accelerating at 1.6 m/s backward. Randomized Variables 880 84 kg m2 110 kg Assignment Status 1.6 Click h A 50% Part (a) What is the magnitude of the force of friction, in newtons. between the losing player's feet and the grass as he slides iled backward Grade Summary Deductions Problem Status tial. Completed sino coso tano 7 8 9 HoME Sub Attempts remaining acoS per attempt 1 2 3 atano acotano sinh0 Completed detailed view cosh( tanho cotanho Completed EVO BACKSPACE CLEAR Degrees O Radians Parti Hint I Submit give up! hint. H remaining Hints deduction per Feedback: 0% deduction per feedback. 10 A 50% Part b) What is the magnitude of the force, in newtons, that the winning player exerts on the ground to move forward if his mass 12 plus equipment is 110 kg? Assume the second player has the same acceleration as the first 13 14 15 Topic 2bb.pptx Search the web and WindowExplanation / Answer
Given that,
F = 880 N ; m1 = 84 kg ; m2 = 110 kg; a = 1.6 m/s2
(a)Let the magnitude of force of friction be F(f).
The net force on the player is :
F(net) = F - F(f) => F(f) = F - F(net)
F(f) = F - ma = 880 N - 84 kg x 1.6 m/s2
F(f) = 880 N - 134.4 N = 745.6 N
Hence, the force of friction between the losing player's feet and grass is = F(f) = 745.6 Newtons.
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