Need help and also I don\'t know how to make velocity vs time graph for this. Ne

Question

Need help and also I don't know how to make velocity vs time graph for this. Need clear and detailed answer please. I am confused at this

you want to visit your friend in Seattle and decide to take the train. Unfortunately, you are late getting to the train station. You are running as fast as you can, but 30 meters ahead of you the train begins to pull out. You can run at a maximum speed of 8 m/s and the train is acceleration at 1 m/s^5. In 50 meters you will reach a barrier. Can you catch up to your train?

Explanation / Answer

Use the kinematic equation for distance travelled S = S0 + 1/2 a*t^2

50 = 30 + 0.5*1*t^2

t^2 = 40

t = 6.325 seconds

Sse now Speed = V = s/t

so time t = S/v

t = 50/8

t = 0.075 secs

So you are at the barrier 0. 075 seconds before the train is there. yes U catchthe train

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