A student stands at the edge of a cliff and throws a stone horizontally over the

Question

A student stands at the edge of a cliff and throws a stone horizontally over the edge with a speed of v0 = 15.5 m/s. The cliff is h = 38.0 m above a flat, horizontal beach as shown in the figure 0 (a) What are the coordinates of the initial position of the stone? x0 = (b) What are the components of the initial velocity? m/s m/s (c) Write the equations for the x- and y-components of the velocity of the stone with time. (Use the following as necessary: t. Let the variable t be measured in seconds. Do not include units in your answer.)

Explanation / Answer

a)

Here ,

initial position of stone ,

x0 = 0 m

y0 = 38 m

b)

initial velocity

v0x = 15.5 m/s

v0y = 0 m/s

c)

as the velocity in x is constant and in y is constant acclerating

vx = 15.5 m/s

vy = -9.8 * t

d)

now , position of stone

x = vx * t

x = 15.5 * t

y = y0 + v0y * t + 0.5 at^2

y = 38 - 4.9 * t^2

e)

for sticking the ground y = 0

0 = 38 - 4.9 * t^2

solving for t

t =2.78 s

the stone strike ground after 2.78 s

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