A passenger rushing to catch a plane at the airport walks on a moving sidewalk a

Question

A passenger rushing to catch a plane at the airport walks on a moving sidewalk at a speed of 3.5 km/h relative to the sidewalk in the direction that the sidewalk is moving. The sidewalk is 110 m long and moves with a steady velocity of 2.0 km/h. How long (in s) does it take for the passenger to get from one end of the sidewalk to the other, that i ­to cover the 110 m?

How much time does the passenger save by taking the moving sidewalk instead of just walking beside it?

Through what distance does the passenger walk relative to the moving sidewalk?

If the passenger's stride is 70 cm, how many steps are taken in going from one end of the moving sidewalk to the other?

Explanation / Answer

(3.5/3.6) = 0.97m/sec.
(2.0/3.6) = 0.55m/sec.
Speed relative to ground using sidewalk = (0.97 + 0.55) = 1.52m/sec.
a) Time on sidewalk = (110/1.52) = 72.3 secs.
Time to walk 110m. not on sidewalk = (110/0.97) = 113.40 secs.
b) (113.40 - 72.3) = 41.1 secs.
c) Passenger is on the sidewalk for 72.3 secs., so distance walked relative to sidewalk = (72.3 x 0.97) = 70.13 metres.
d) 70 cm = 0.70m.
(70.13/0.70) = 100 steps

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