In one of its aid missions in a drought affected region, Red Cross decides to ai

Question

In one of its aid missions in a drought affected region, Red Cross decides to airdrop food packets using a single engine propeller aircraft flying at low altitude.

At the instant the packets are dropped, the aircraft is flying 30.0 m above ground-level and traveling at a constant velocity with components 10.0 m/s upward and 15.0 m/s horizontal.

At what horizontal distance, relative to the location of the aircraft when the packets are dropped, will the packets land on the ground? Assume that the terrain is flat and air resistance is negligible.

Explanation / Answer

Let horizontal distance is X, Ux is initial velocity in x direction, Uy is initial velocty in y direction

now using equation of motion

X= (Ux)*t ( a =0)

X = 15*t

Y = (Uy)*t + 1/2*a*t^2

0-30 = 10t - 1/2*9.8*t^2

solving this we get t =3.69 sec

X= 15*3.69 = 55.35m

yes it will land on ground

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