1) In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done by the

Question

1) In the drawing above, E = 4.0N/C and d = 1.5m. Calculate the work done by the electric field in moving a +5.0x10-9C charge from A to B. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question.

2) In the situation in diagram above, calculate the potential energy difference between the +5.0x10-9C charge at B and at A. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question.

3) For the situation in diagram above, calculate the potential difference between A and B. Be sure to include - sign if your answer is negative. Your answer needs to be in V but you don't need to enter the unit in your answer for this question.

Explanation / Answer

here,

A)

E = 4 N/C

the work done by the electric feild , W = electric Force * d * cos(theta)

theta = angle between the displacement and the electric feild

here theta = 90 degree

therefore the work done in moving the charge is 0

B)

change in potential energy , U = - work done by the electric feild

therefore ,

the potential energy difference between the +5.0x10-9C charge at B and at A is 0

C)
change in potential = change in potential energy /charge

therefore ,

the potential difference between point A and B is 0

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