A 60 kg skier skis directly down a frictionless slope angled at 17 degree to the

Question

A 60 kg skier skis directly down a frictionless slope angled at 17 degree to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component F acts on the skier. (Indicate the direction with the sign of your answer.) (a) What is Fx if the magnitude of the skiers velocity Is constant? (b) What Is Fx if the magnitude of the skiers velocity Is increasing at a rate of 3.0 m/s^2? (c) What is Fx if the magnitude of the skiers velocity is increasing at a rate of 6.0 m/s^2?

Explanation / Answer

Here ,

a)

if the skier moves with constant velocity

net force in the parallel is zero

Fx - mg * sin(17) = 0

Fx - 60* 9.8 * sin(17) = 0

Fx = 171.9 N

the magnitude of force Fx is 171.9 N

b)
for a = 3 m/s^2

Fx - mg * sin(theta) = ma

Fx - mg * sin(17) = -3 * 60

Fx = 60* 9.8 * sin(17) - 180

Fx = -8.1 N

the wind force Fx is -8.1 N

c)

for a = 6 m/s^2

Fx - mg * sin(theta) = ma

Fx - mg * sin(17) = -6 * 60

Fx = 60* 9.8 * sin(17) - 360

Fx = -188.1 N

the wind force Fx is -188.1 N

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