hello, need some help on #47, i know the first part but dont know how to solve p
ID: 1327596 • Letter: H
Question
hello, need some help on #47, i know the first part but dont know how to solve part b and c,thanks
Explanation / Answer
(a) energy of capacitor is given by E = 0.5*CV²
C= 3x10-6 F, V =6V
so , energy = 0.5 *3x10-6 F *6V
=5.4x10-5 J= 54 microjoule
2) charge on each plate initially is Q=CV = 3x10-6 * 6 = 18 x10-6 C
now when the plates are separated , the charge remain same,but capacitance decrease by half
since C = (epsilono*A)/d
so , new capacitanceC = 1.5 x10-6 F
now , energy stored in new capacitor will be 0.5 Q2/C
=0.5 * (18 x10-6 C)2 / (1.5 x10-6 F)
energy stored =1.08x10-4 J = 108 microjoule
c) Required Energy = 0.5*1.5 x10-6 F *6V² =2.7 x10-5 J = 27 microjoule
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