a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.0

Question

a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels? a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels? a girl delivering newspapers covers her route by traveling 3.00 blocks west, 4.00 blocks north, and then 6.0 blocks east. A) what is the magnitude of her resultant displacement?B) what is the total distance she travels?

Explanation / Answer

a)

here

x components = -3 blocks , +6 blocks

y components = +4 blocks

the component of the resultants are

Rx = -3 + 6 = 3 blocks

Ry = 4 blocks

the magnitude and direction of the resultant are then given by

R = sqrt( Rx^2 + Ry^2)

R = sqrt( 3^2 + 4^2) = 5 blocks

then

theta = tan^-1(Ry / Rx) = 53.1 deg north of east

b)

the distance traveled is

d = (3 + 4+ 6 )blocks = 13 blocks

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