Exercise 3.27 A Ferris wheel with radius 14.0 m is turning about a horizontal ax
ID: 1327486 • Letter: E
Question
Exercise 3.27 A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center in (Figure 1) The linear speed of a passenger on the rim is constant and equal to 7.20 m/s Figure 1 of 1 Part A What is the magnitude of the passengers acceleration as she passes through the lowest poi in her circular motion? Express your answer with the appropriate units. a 6.09 im Submit My Answers Give U Incorrect, Try Again, 4 attempts remaining Part B What is the direction of the passenger's acceleration as she passes through the lowest point in her circular motion? towards the center outwards the center My Answers Give Up Correct Part C What is the magnitude of the passengers acceleration as she passes through the highest point in her circular motion? Express your answer with the appropriate units.Explanation / Answer
Let:
r be the radius,
v be the passenger's speed,
a be the acceleration,
t be the time for one revolution.
a = v^2 / r
= 7.20^2 / 14.0
= 3.70 m/s^2 to 3 sig. fig.
The acceleration is constant in magnitude, and directed towards the centre of the wheel.
At the bottom, it is 3.70 m/s^2 upwards.
At the top, the acceleration is 3.70 m/s^2 downwards.
t = 2pi r / v
= 2pi * 14.0 / 7.20
= 12.21 sec.
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