Exercise 3.16 On level ground a shell is fired with an initial velocity of 42.0

Question

Exercise 3.16 On level ground a shell is fired with an initial velocity of 42.0 m/s at 53.0 degree above the horizontal and feels no appreciable air resistance. Part D How far from its firing point does the shell land? Express your answer using three significant figures. Part E At its highest point, find the horizontal and vertical components of its acceleration. Enter your answers numerically separated by a comma. Part F At its highest point, find the horizontal and vertical components of its velocity Enter your answers numerically separated by a comma.

Explanation / Answer

given,

velocity = 42 m/s

angle = 53 degree

time rquired to reach heighest point = t

by first equation of motion

v = u + at

0 = 42 * sin(53) - 9.8 * t

t = 3.42 sec

horizontal distance = horizontal velocity * time of flight

horizontal distance = 42 * cos(53) * 3.42 * 2

horizontal distance = 172.89 m

at highest point

horizontal acceleration = 0 m/s^2

vertical acceleration = 9.8 m/s^2

horizontal velocity = 42 * cos(53)

horizontal velocity = 25.27 m/s

vertical velocity = 0 m/s

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.