A customer sits in an amusement park ride in which the compartment is to be pull
ID: 1327296 • Letter: A
Question
A customer sits in an amusement park ride in which the compartment is to be pulled downward in the negative direction of a y axis with an acceleration magnitude of 1.38 g, with g = 9.80 m/s2. A 0.339 g coin rests on the customer's knee. Once the motion begins and in unit-vector notation, what are projections of the coin's acceleration relative to the ground on(a)x-axis, (b)y-axis, (c)z-axis and relative to the customer on (d)x-axis, (e)y-axis, (f)z-axis? (g) How long does the coin take to reach the compartment ceiling, 2.5 m above the knee? What are projections of the actual force on the coin on (h)x-axis, (i)y-axis, (j)z-axis and projections of the apparent force according to the customer's measure of the coin's acceleration on (k)x-axis, (l)y-axis, (m)z-axis?
Explanation / Answer
Acceleration of the compartment = -g jm/s2
Since coin is in free fall, the acceleration of the coin with respect to ground is,
a= -gj m/s2
= -9.8 j m/s2
(a)
The acceleration of the coin with respect to ground on x-axis is
ax=0 m/s2
(b)
Since coin is in free fall, the acceleration of the coin with respect to ground on y-axis is,
ay= -gj m/s2
= -9.8 j m/s2
(c)
The acceleration of the coin with respect to ground on z-axis is
az=0 m/s2
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The acceleration of the coin with respect to customer is,
a customer = (1.38 - 1)gj m/s2
= 0.38g j m/s2
= 3.724 j m/s2
(d)
The acceleration of the coin with respect to customer on x-axis is
ax, customer =0 m/s2
(e)
The acceleration of the coin with respect to customer on y-axis is
ay, customer =3.724 j m/s2
(f)
The acceleration of the coin with respect to customer on z-axis is
az, customer =0 m/s2
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