1. A certain car is capable of accelerating at a rate of 0.55 m/s 2 . How long d

Question

1. A certain car is capable of accelerating at a rate of 0.55 m/s2. How long does it take for this car to go from a speed of 33 mi/h to a speed of 51 mi/h? in seconds

2. An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.06 cm. If its x-coordinate 2.25 s later is 5.00 cm, what is its acceleration? ___ cm/s^2

(a) Draw a coordinate system for this situation and label the relevant quantities, including vectors. (Do this on paper. Your instructor may ask you to turn in this work.)

(b) For the given information, what single equation is most appropriate for finding the acceleration? (Do this on paper. Your instructor may ask you to turn in this work.)

(c) Solve the equation selected in part (b) symbolically for the boat's acceleration in terms of vf, vi, and x. (Do this on paper. Your instructor may ask you to turn in this work.)

(d) Substitute given values, obtaining the acceleration.
m/s2

(e) Find the time it takes the boat to travel the given distance.
s

4. A jet plane lands with a speed of 102 m/s and can accelerate at a maximum rate of 5.50 m/s2 as it comes to rest.

(a) From the instant the plane touches the runway, what is the minimum time needed before it can come to rest?
s

(b) Can this plane land on a small tropical island airport where the runway is 0.800 km long?

Yes or No?

5. A car accelerates uniformly from rest to a speed of 30.0 mi/h in 13.0 s.

(a) Find the distance the car travels during this time.
___ m

(b) Find the constant acceleration of the car.
___ m/s2

THANK YOU SO MUCH!

Explanation / Answer

1)
a = 0.55 m/s2
Initial speed = 33 mi/h = 14.75 m/s
Final speed = 51 mi/h = 22.8 m/s

v = u + a*t
22.8 = 14.75 + 0.55 * t
t = (22.8 -14.75)/0.55 s
t = 14.64 s
Time taken by the car to reach speed of 33 mi/h to a speed of 51 mi/h t = 14.64 s


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