arPolnt Ea Vew Window Help Hydrogen atom a.) In the Bohr model of the hydrogen a
ID: 1327183 • Letter: A
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arPolnt Ea Vew Window Help Hydrogen atom a.) In the Bohr model of the hydrogen atom, in which the electron orbits the nucleus much like planets orbit the sun, what is the smallest amount of work that must be done on the electron to move it from its circular orbit, with a radius of 0.529x10-10 m, to an infinite distance from the proton (the nucleus)? This value is referred to as the ionization energy of hydrogen. [Hint: don't forget that initially, the electron going around the proton has a kinetic energy in addition to the potential energy.] b) Through what potential difference does the electron move as this work is being done on it? Does its potential increase or decrease? .Explanation / Answer
Given that,
R = 0.529 x 10-10 meters.
total energy for any moving object is the sum of its kinetic and potential energies KE + PE. We know from orbital mechaniccs that the total energy KE+ PE is one half of PE
W = (KE + PE) = 1/2 PE
We know that electric potential energy (PE) = electric force x distance = k q1 q2 / r2 x r = k q1 q2 / r
we have, q1 = q2 = e= 1.6 x 10-19 C and k = 9 x 109 N m2 /C2.
PE = 9 x 109 N m2 /C2 x 1.6 x 10-19 C x 1.6 x 10-19 C / 0.529 x 10-10 m = 4.355 x 10-18 J
We got, PE = 4.355 x 10-18 J
W = PE/2 = 4.355 x 10-18 J / 2 = 2.178 x 10-18 J
Hence, W = 2.178 x 10-18 J
(b) V = PE / q = 4.355 x 10-18 J / 1.6 x 10-19 C = 27.22 Volts
Hence, V = 27.22 Volts.
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