Two loudspeakers are placed 3.00 m apart, as shown in the figure below. They emi

Question

Two loudspeakers are placed 3.00 m apart, as shown in the figure below. They emit 478-Hz sounds, in phase. A microphone is placed 3.20 m distant from a point midway between the two speakers, where an intensity maximum is recorded.

How far must the microphone be moved to the right to find the first intensity minimum?

I have tried and it is not 0.355m. I repeat it is not 0.355m.

Two loudspeakers are placed 3.00 m apart, as shown in the figure below. They emit 478-Hz sounds, in phase. A microphone is placed 3.20 m distant from a point midway between the two speakers, where an intensity maximum is recorded. How far must the microphone be moved to the right to find the first intensity minimum? I have tried and it is not 0.355m. I repeat it is not 0.355m.

Explanation / Answer

lambda = v/f = 343/478 = 0.7175 m

d1' = sqrt(3.2^2 + (1.5-x)^2)

d2' = sqrt(3.2^2 + (1.5+x)^2)

d2' - d1' = lambda/2 = 0.358 m

sqrt(3.2^2 + (1.5+x)^2) - sqrt(3.2^2 + (1.5-x)^2) = 0.358

x = 0.424 m

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