Review Conceptual Example 2 as an aid in understanding this problem. A velocity

Question

Review Conceptual Example 2 as an aid in understanding this problem. A velocity selector has an electric field of magnitude 2050 N/C, directed vertically upward, and a horizontal magnetic field that is directed south. Charged particles, traveling east at a speed of 6.38 x 10^3 m/s, enter the velocity selector and are able to pass completely through without being deflected. When a different particle with an electric charge of +4.60 x 10^-12 C enters the velocity selector traveling east, the net force (due to the electric and magnetic fields) acting on it is 1.81 x 10^-9 N, pointing directly upward. What is the speed of this particle?

Explanation / Answer

Here ,

as for undeflected particles

u*B = E

B = 2050/6.38 *10^3

B = 0.321 T , it is in south direction

Now , for the second particle

Fnet = qE - quB

1.81 *10^-9 = 4.6*10^-12 * (2050 - u*0.321)

solving for u

u = 5160 m/s

the speed of particle is 5160 m/s

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