An object 1.80 cm tall is placed 100 cm in front of a diverging lens having a fo

Question

1. An object 1.80 cm tall is placed 100 cm in front of a diverging lens having a focal length of magnitude 25 cm. A converging lens with a focal length of magnitude 33.33 cm is placed 30 cm past the first lens. What is the lateral magnification of this system of lenses? 2.5 -2.5 -0.40 1.0 0.40

1. An object 1.80 cm tall is placed 100 cm in front of a diverging lens having a focal length of magnitude 25 cm. A converging lens with a focal length of magnitude 33.33 cm is placed 30 cm past the first lens. What is the lateral magnification of this system of lenses? 2.5 -2.5 -0.40 1.0 0.40

An object 1.80 cm tall is placed 100 cm in front of a diverging lens having a focal length of magnitude 25 cm. A converging lens with a focal length of magnitude 33.33 cm is placed 30 cm past the first lens. What is the lateral magnification of this system of lenses? 2.5 -2.5 -0.40 1.0 0.40 An object 1.80 cm tall is placed 100 cm in front of a diverging lens having a focal length of magnitude 25 cm. A converging lens with a focal length of magnitude 33.33 cm is placed 30 cm past the first lens. What is the lateral magnification of this system of lenses? 2.5 -2.5 -0.40 1.0 0.40 2.5 -2.5 -0.40 1.0 0.40

Explanation / Answer

First for the diverging lens

1/f 1/p + 1/q

1/-25 = 1/100 + 1/q

q = -20 cm (20 cm in front of the diverging lens)

That is 50 cm in front of the converging lens, so...

For the converging lens

1/33.3 = 1/50 + 1/q

q = 99.7 cm

M = -q/p times -q/p

M = -(-20)/100 times -99.7/50

M = -.40

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