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2. Young\'s modulus of nylon is 3.7 10 9 N/m 2 . A force of 2.2 10 6 N is applie

ID: 1324112 • Letter: 2

Question

2. Young's modulus of nylon is 3.7 109 N/m2. A force of 2.2 106 N is applied to a 1.2 m length of nylon of cross sectional area 0.18 m2. By what amount does the nylon stretch?

3. The shear modulus of steel is 8.1 1010 N/m2. A steel nail of radius 5.7 104m projects 0.036 m horizontally outward from a wall. A man hangs a wet raincoat of weight 26.8 N from the end of the nail. Assuming the wall holds its end of the nail, what is the vertical deflection of the other end of the nail?

1.A 0.20 kg block is held in place by a force that results in a 0.16 m compression of a spring beneath the block. The spring constant is 1.1 ½ 102 N/m. Assuming the mass of the spring is negligible compared to that of the block, to what maximum height would the block rise if the force 2. Young's modulus of nylon is 3.7 i 1/2 109 N/m2. A force of 2.2 i 1/2 106 N is applied to a 1.2 m length of nylon of cross sectional area 0.18 m2. By what amount does the nylon stretch? 3. The shear modulus of steel is 8.1 I 1/2 1010 N/m2. A steel nail of radius 5.7 I 1/2 10 I 1/2 4m projects 0.036 m horizontally outward from a wall. A man hangs a wet raincoat of weight 26.8 N from the end of the nail. Assuming the wall holds its end of the nail, what is the vertical deflection of the other end of the nail? FV were removed.

Explanation / Answer


1. apply EPE = KE

0.5 kx^2 = mgh

h = 0.5 * 110 * 0.16*0.16/(0.2* 9.8)

h = 0.718 m

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2. Youngs modlulus Y of a material is given Y = FL/ADL

A = area

DL = change of length

L = original length

F = force

so here we apply DL = FL/AY

DL   = 2.2 e 6 * 1.2/(3.7 e9 * 0.18)

DL = 3.96 mm

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DL = 26.8 * 0.036/(8.1 e10 * 3.14 * 5.7e-4*5.7e-4)

DL = 11.67 um

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