Driving home from school one day, you spot a ball rolling out into the street (s

Question

Driving home from school one day, you spot a ball rolling out into the street (see the figure (Figure 1) ). You brake for 1.50s , slowing your 910-kg car from 16.0 m/s to 9.50 m/s.

Part A

What was the magnitude of the average force exerted on your car during braking?

ANSWER: 3900 N

Part B

What was the direction of the average force exerted on your car during braking?

ANSWER: OPPOSITE TO THE DIRECTION OF MOTION.

MY QUESTION***

Part C

Driving home from school one day, you spot a ball rolling out into the street (see the figure (Figure 1) ). You brake for 1.50s , slowing your 910-kg car from 16.0 m/s to 9.50 m/s. Part A What was the magnitude of the average force exerted on your car during braking? ANSWER: 3900 N Part B What was the direction of the average force exerted on your car during braking? ANSWER: OPPOSITE TO THE DIRECTION OF MOTION. MY QUESTION*** Part C How far did you travel while braking? (find delta x; answer in m)

Explanation / Answer

1) final v = 9.50 m/s
initial u = 16 m/s
using , v - u = at
9.50 - 16 = a * 1.50
a = -4.33 m/s2
F = ma = 910 x -4.33 = - 3940.3 N
magnitude = 3940 N

b)   direction = oppposite of velcoity direction
means in backward direction

c) v^2 - u^2 = 2ad
d = 9.50^2 - 10^2 / 2*-4.33   = 19.12 m

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