Three resistors with resistances R1 = 57.0 ?, R2 = 18.0 ? and R3 = 32.0 ? are pl
ID: 1323639 • Letter: T
Question
Three resistors with resistances R1 = 57.0 ?, R2 = 18.0 ? and R3 = 32.0 ? are placed along the sides of a triangle as shown in circuit 1. What are the values of the resistances Ra, Rb and Rc that would provide an equivalent circuit as arranged in circuit 2?
889/1 CakculatorPeriodic T alcuato Quetion 3o115 Three resistors with resistances R1-570 Rz-18.0 and R3-32.0 are placed along the sides of a triangle as shown in circuit 1. What are the values of the resistances R, R and Re that would provide an equivalent circuit as arranged in circuit 2? Number Number Number Circuit 2Explanation / Answer
Ra = Rb parallel Rc and then it is series with Ra
Ra = 32* 18/(32+18) + 57
Ra = 68.52 ohms
------------
Rb = Ra Parallel Rc , then series with Rb
so
Rb = 57 * 32/(57+32) + 18
Rb = 38.49 ohms
------------
Rc = Ra parallel Rb ,series with Ra
Rc = 57* 18/(57+18) + 32
Rc = 45.68 ohms
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.