please help me with this question. thank you A m 1 = 1.75-kg aluminum block and

Question

please help me with this question. thank you

A m1 = 1.75-kg aluminum block and a m2 = 6.05-kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle

? = 32.0?)

as shown in the figure. Making use of this table, determine the following.

(a) the acceleration of the two blocks
____________ m/s2

(b) the tension in the string

____________ N

please help me with this question. thank you A m1 = 1.75-kg aluminum block and a m2 = 6.05-kg copper block are connected by a light string over a frictionless pulley. The two blocks are allowed to move on a fixed steel block wedge (of angle ? = 32.0) as shown in the figure. Making use of this table, determine the following. (a) the acceleration of the two blocks ____________ m/s^2 (b) the tension in the string ____________ N

Explanation / Answer

Assume that the copper block moves down and aluminum block moves up the plane.

The net gravitational force pulling both masses together is (6.05 - 1.75) kg = 4.3 kg

.The opposing frictional forces is (0.47*1.75 + 0.36*6.05) kg *cos 32= 2.544 kg

The net downward acceleration is 6.05kg - 2.544 kg = 3.505 kg

Acceleration = force /mass = 3.505*9.8 / (6.05 + 1.75) = 4.404 m/s^2
===================
The force (T - 2g -0.47*2g cos 32) pulls the aluminum block upward with an acceleration of 4.404 m/s^2
( T - 2*9.8 -0.47*2*9.8*cos 30 ) = 2* 4.404
T = 36.22 N

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