The force acting on a particle varies as shown in the figure below. (The x axis

Question

The force acting on a particle varies as shown in the figure below. (The x axis in the graph is marked in increments of 5.00 m.)

Find the work done by the force on the particle as it moves across the following distances.

(a) from x = 0 m to x = 40.00 m
J

(b) from x = 40.00 m to x = 60.00 m
J

(c) from x = 0 m to x = 60.00 m
J

The force acting on a particle varies as shown in the figure below. (The x axis in the graph is marked in increments of 5.00 m.) Find the work done by the force on the particle as it moves across the following distances. (a) from x = 0 m to x = 40.00 m J (b) from x = 40.00 m to x = 60.00 m J (c) from x = 0 m to x = 60.00 m J

Explanation / Answer

Work Done in defined as the product of force and distnace

here the area under graph represents work done

so

A: from x = 40 -0 = 40 m

work Done = Area of trinalge

W = 0.5 b h

W = 0.5 *

force F = (0.5 * 6 * 40)

F = 120 N

-----------------

from x = 40 t0 60

Area A   = W = 0.5* (60-40) * -2

W = -20 Joules

------------------------------

from 0 to 60

it is Wnet = 120 -20 = 100 N

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