1. In the circuit above, the voltage across the battery, V, is 76.0 V, and the r
ID: 1323155 • Letter: 1
Question
1. In the circuit above, the voltage across the battery, V, is 76.0 V, and the resistances are R2=8.0 ?, R1=6.0 ?, and R3=2.0 ?.
What is the current through resistor R2?
2. What is the current through resistor R1?
3. What is the current through resistor R3?
4. What is the voltage difference across resistor R2?
5. What is the voltage difference across resistor R1?
6. What is the voltage difference across resistor R3?
7. What is the total current through the battery?
1. In the circuit above, the voltage across the battery, V, is 76.0 V, and the resistances are R2=8.0 ?, R1=6.0 ?, and R3=2.0 ?. What is the current through resistor R2? 2. What is the current through resistor R1? 3. What is the current through resistor R3? 4. What is the voltage difference across resistor R2? 5. What is the voltage difference across resistor R1? 6. What is the voltage difference across resistor R3? 7. What is the total current through the battery?Explanation / Answer
R1 and R3 are parallel to each other.
Thus,
R(1 parallel 3) = 1.5 ohms
This is parallel to R2. Thus,
Rnet = 9.5 ohms
Thus, the net current in the circuit is
Inet = V/Rnet = 8.0 A
Which is also the current for R2,
I2 = 8.0 A [PART 1, ANSWER]
***********
The current through resistors R1 and R3 are separated, inversely proportional to their resistances.
Thus, 8 A will be split accordingly,
I1 = 2.0 A [PART 2, ANSWER]
I3 = 6.0 A [PART 3, ANSWER]
************
V2 = I2R2 = 8.0 A (8 Ohms) = 64 V [PART 4, ANSWER]
V1 = I1R1 = 2.0 A (6 ohmS) = 12 V [PART 5, ANSWER]
V3 = I3R3 = 6.0 A (2 ohms) = 12 V [PART 6, ANSWER]
************
As we said already earlier,
Inet = 8.0 A [PART 7, ANSWER]
DONE! It was nice working with you!
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