1. Three uniform spheres of masses m 1 = 3.50 kg, m 2 = 4.00 kg, and m 3 = 7.00
ID: 1322783 • Letter: 1
Question
1. Three uniform spheres of masses m1 = 3.50 kg, m2 = 4.00 kg, and m3 = 7.00 kg are placed at the corners of a right triangle (see figure below). Calculate the resultant gravitational force on the object of mass m2, assuming the spheres are isolated from the rest of the Universe.
_______ m/s
A rocket is fired straight up through the atmosphere from the South Pole, burning out at an altitude of 247 km when traveling at 4.90 km/s. What maximum distance from the launch site does it travel before falling back to Earth?
____ m
(______ i + _________ J) x 10^-11 N 1. Three uniform spheres of masses m1 = 3.50 kg, m2 = 4.00 kg, and m3 = 7.00 kg are placed at the corners of a right triangle (see figure below). Calculate the resultant gravitational force on the object of mass m2, assuming the spheres are isolated from the rest of the Universe. (______ i + _________ J) x 10^-11 N x 104 m/s. What will its speed be when it is very far from the Earth? Ignore atmospheric friction and the rotation of the Earth. _______ m/s A rocket is fired straight up through the atmosphere from the South Pole, burning out at an altitude of 247 km when traveling at 4.90 km/s. What maximum distance from the launch site does it travel before falling back to Earth? ____ m 2. A space probe is fired as a projectile from the Earth's surface with an initial speed of 1.58Explanation / Answer
Note that the gravitational force on 2 objects is
F = G mA mB/r^2
where
G = 6.67 N m^2/kh^2
mA, mB = interacting masses
r = distance between mA and mB
Thus, for the force due to m1,
For m1 = 3.50 kg, m2 = 4.00 kg, as r12 = 3.00 mm
F(m2 by m1) = 1.04E-10 j^ N
For the force due to m3 = 7.00 kg, r23 = 4.00 m,
F(m3 on m2) = -1.17E-10 i^ N
Thus,
Fnet = ( -1.17E-10 i^ + 1.04E-10 j^) N
or
Fnet = ( -11.7 i^ + 10.4 j^) *10^-11 N
DONE! It was nice working with you!
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