KIRCHHOFF?S CIRCUIT Laws 1. Find the equivalent resistance of the following netw
ID: 1322571 • Letter: K
Question
KIRCHHOFF?S CIRCUIT Laws 1. Find the equivalent resistance of the following network. (All resistances are in ohms.) Show your work below. 2. Show on the circuit diagram in Question 1 how you would connect a multi- meter to measure the current through the 8- Omega resistor. a. Explain why the millimeter is connected in this way. b. What design feature of a good millimeter allows you to connect it in the way indicated without appreciably affecting the current through the 8-fl resistor? 3. Show on the circuit diagram in Question 1 how you would conned a multi- meter to measure the voltage across the 8-fl resistor. a. Explain why the millimeter is connected in this way. b. What design feature of a good millimeter allows you to connect it in the way indicated without appreciably affecting the voltage across the 8-fl resistor? . 4. Pictured in the thick-lined box in the circuit on the right is a battery with emf 12 V and internal resistance 1 Omega. A is the positive terminal of the battery and B is the negative terminal. a. What is the potential difference across the battery?s terminals when the switch S is open, as shown?Explanation / Answer
part 1:
when resistances are connected in series, RNet = R1+ R2
and in parallel, Rnet = R1*R2/(R1+R2)
so
here
10 and 10 are in sereis = 20 ohms
20 is in paralllel withj 20
Rnet = 20*20/(20+20)
Rnet = 40 ohms
40 is in sereis with 20 = 60 ohms
20 , 30 are in parallel , R' -= 20*30/50 = 12 ohms
12, 8, 10 are in series = 30 ohms
finally 30 and 60 are in parallel
so
RNet = 30*60/(90)
Rnet = 20 ohms is the net Resisatnce
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