1 . Consider a charged particle traveling at theta = 30 degree with respect to a

Question

1 . Consider a charged particle traveling at theta = 30 degree with respect to a uniform magnetic field of strength B = 2.6 mT as shown below. The particle has speed v = 3.0 x 10^6 m/s. a) If the particle is a proton, what is the magnitude and direction (into or out of the page) of the force exerted on the particle by the magnetic field? b) If the particle is an electron instead, how would your answer change? What direction does Earth's magnetic field point in Toledo? Does the direction change as you move North? South? How about right at the (magnetic) North pole? Hint: Earth's magnetic field is produced by a bar magnet.

Explanation / Answer

1) a )Force = e . (V X B) = 1.6 *10^(-19) * 3*10^(6) *2.6*10^(-3) * sin(30) = 6.24 *10 ^(-16) N (ans)

Direction of this force will be out of plane (ans)

b) If proton is replaced by electron

Then force magnitude will remain same ,F = 6.24 *10 ^(-16) N (ans)

But direction will be opposite and will be into the plane   (ans)

2) Magnetic field wont change with movement towards north or south (ans)

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.