Two teams of none members each engage in a tug of war. The first team\'s members

Question

Two teams of none members each engage in a tug of war. The first team's members have average masses of 67 kg and exert average forces of 1350 N horizontally. The second team's members have average masses of 72 kg and exert average forces of 1357 N horizontally. (a) What is the acceleration of the two teams? m/s^2 (in the direction me heavy team is pulling) (b) What is the tension on the section of rope between the teams? Suppose a 59.0-kg gymnast climbs a rope. (a) What is the tension in the rope if he climbs at a constant speed? (b) What is the tension in the rope if he accelerates upward at a rate of 1.35 m/s^2?

Explanation / Answer

F = ma
a = F / m

where the Force is the net force and m is the total mass

a = 9(1357 - 1350) / 9(67 + 72)
a = 0.0503 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.