Lab #4.) 0.15 M NaCL (u Bradford Regant Protein (uE/tube) AS95 2.5 2.5 2.5 Sampl
ID: 132237 • Letter: L
Question
Lab #4.) 0.15 M NaCL (u Bradford Regant Protein (uE/tube) AS95 2.5 2.5 2.5 Sample Source Tube N Inverse Powers Bradford Regeant (mL) AS95 Dilution Factor Protein (ug/tube 96.71232877 29.7260274 100 7,260273973 0 0.118 20 0165 00.203 40 0249 50 0.391 M1 M2 1:10 0.1 M3 0.1111 0.01 10.001 2.5 0.70 2.5 0217 2.5 0053 10 30 2.5 WG1 2.5 0756 2.5 0.478 2.5 0054 2.5 006 1103.5516438 0.1 WG3 0.1111 0.01 Wheat germ WG4 0.7361 0.001 1:10 07397260274 8.630136986 008 BSA Standard Curve 2900885382 0 290088538 035 Protein (etube) Please calculate the . the original unknown protein concentration(s)Explanation / Answer
The concentration of the unknown protein sample can be calculated from the standard curve obtained after reading the absorbance of BSA. The graph gives a straight line under ideal conditions and the equation of the slope of the graph. This equation of the slope can be directly used to calculate any value of unknown or 'x' such as in sample. Hence, the information states that the equation for this standard curve is given by:
y = 0.0003x, where y is the value of absorbance read in the spectrophotometer and x is the value of unknown. Thus, the values of unknown protein concentrations can be calculated as below:
M1 = 0.706/0.0003 * 1 (DILUTION FACTOR)
Thus, concnetration of M1 = 2353.33 ug/tube
Similarly, the values of other unknown proteins can be calculated as below:
M2 = 0.217 * 0.1 / 0.0003 = 72.33 ug/tube
M3 = 0.053 * 0.01 / 0.0003 = 1.77 ug/tube
WG1 = 0.756 * 1 / 0.0003 = 2520 ug/tube
WG2 = 0.478 * 0.1 / 0.0003 = 159.33 ug/tube
WG3 = 0.054 * 0.01 / 0.0003 = 1.8 ug/tube
WG4 = 0.063 * 0.001 / 0.0003 = 21 ug/tube
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