As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is p
ID: 1321982 • Letter: A
Question
As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is pushed a distance d = 95.0 m across a rough warehouse floor by an applied force of FA = 238 N directed at an angle of 30.0 below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.)
(d) work done by the force of friction in joules
As shown in the figure below, a box of mass m = 61.0 kg (initially at rest) is pushed a distance d = 95.0 m across a rough warehouse floor by an applied force of FA = 238 N directed at an angle of 30.0½ below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) (d) work done by the force of friction in joulesExplanation / Answer
Here ,
N = mg + F*sin(30)
N = 61*9.8 + 238 * sin(30)
N = 716.8 N
Now , friction = u*N
friction = 0.10 * 716.8
friction = 71.68 N
WOrk done by friction = force * distance
WOrk done by friction = -71.68 * 95
WOrk done by friction =-6809.6 J
WOrk done by friction is -6809.6 J
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