A 30.0-kg block is resting on a flat horizontal table. On top of this block is r

Question

A 30.0-kg block is resting on a flat horizontal table. On top of this block is resting a 15.0-kg block, to which a horizontal spring is attached, as the drawing illustrates. The spring constant of the spring is 340 N/m. The coefficient of kinetic friction between the lower block and the table is 0.590, and the coefficient of static friction between the two blocks is 0.870. A horizontal force is applied to the lower block as shown. This force is increasing in such a way as to keep the blocks moving at a constant speed. At the point where the upper block begins to slip on the lower block determine the following. (a) the amount by which the spring is compressed m (b) the magnitude of the force N

Explanation / Answer

Apply tension T =   N-mg

as fig if missing, iam just giving out the procedure

so

mass m = 60/9.81 = 6.11 Kgs

tension T = N-mg

apply frictional force F = umg

net normal force N on spring = 15* 0.87 * 9.8 = 127.89 N

now use F = kx

x = 127.89/340

x = 0.376 m

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magnitude of force F =   15* 0.87 * 9.8 = 127.89 N

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