(b) Keeping the simulation in double-slit mode, set the slit width to 0.05 mm so

Question

(b) Keeping the simulation in double-slit mode, set the slit width to 0.05 mm so you see many bright fringes on the screen. Now set the slit separation to 2.0 mm.

(i) Counting the central maximum (the brightest fringe) as zero, what should you set the slit width to so the fifth fringe to the left or right of the central maximum vanishes, but all the fringes closer to the central maximum are still visible? Think of how can you change the number of visible fringes, use the simulation to find the answer.

___________mm

(ii) From the simulation, what is the ratio of the slit separation to the slit width in this situation?

__________

Explanation / Answer

A. apply Y = mLR/d

Y is fringe width

d is slit widht

so

Y2/Y1 = d1/d2

Y2 = Y1 * 2/0.05

Y2 = 40 times Y1

---------------------------------

Y2 = 5 times om actual fringe distance

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y/D   = M2/M1

y/d = 5/1 = 5

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