Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Genetics problem. Please show all work. thank you so much 1. Two pure breeding p

ID: 132086 • Letter: G

Question

Genetics problem.

Please show all work. thank you so much

1. Two pure breeding plants with the genotypes ddPP and DDpp are crossed together to generate F1 progeny with the genotype DdPp. F1 individuals were testcrossed to a homozygous parental strain (ddpp). The following data were obtained: Genotype DdPp Ddpp Ddpp ddPp observed # of progeny Expected # of progeny 190 210 310 290 Total: 1000 A. In the table above, fill in the values for the expected number of progeny for each genotype based on the hypothesis that D and P are unlinked B. What is the calculated ?2 value? C. How many degrees of freedom are there? D. Are D and P linked or unlinked? (Use the 2 table attached below) E. Briefly explain how the ?2 analysis supports your conclusion. 0.999 0.995 0.999 0.975 0.95 0.9 0.5 0.1 0.05 0.025 0.01 0.005 0.001 1 0.000 0.000 0.000 0.001 0.0040.016 0.455 2.7063.8 5.024 6.6357.879 10.828 2 0.002 0.010 0.002 0.051 0.1030.211 1.386 4.605 5.9917.378 9.210 10.597 13.816 3 0.024 0.072 0.024 0.216 0.352 0.584 2.366 6.251 7.8159.34811.345 12.838 16.266 4 0.091 0.207 0.091 0.484 0.7111.064 3.357 7.779 9.488 11.143 13.277 14.860 18.467 5 0.210 0.412 0.210 0.831 1.145 1.610 4.351 9.236 11.070 12.833 15.086 16.750 20.515 115 73.761 79.692 73.761 87.213 91.242 96.043 114.334 134.813 141.030 146.571 153.191 157.808 167.610 116 74.55880.522 74.558 88.084 92.13496.958 115.334 135.898 142.138 147.700 154.344 158.977 168.813 117 75.35681.353 75.356 88.955 93.026 97.874 116.334 136.982 143.246 148.829 155.496 160.146 170.016 118 76.15582.185 76.155 89.82793.918 98.790 117.334 138.066 144.354 149.957 156.648 161.314 171.217 119 76.955 83.018 76.955 90.700 94.811 99.707 118.334 139.149 145.461 151.084 157.800 162.481 172.418 120 77.755 83.852 77.755 91.573 95.705 100.624 119.334 140.233 146.567 152.211 158.950 163.648 173.617

Explanation / Answer

Answer:

A).

B). X2 value = 41.60

C). Degrees of freedom = number of categories - 1

= 4-1=3

D). D and P are linked

E). A chi-square of 41.60 is greater than the critical value (7.815), so we CAN reject the null hypothesis. Genes are linked.

Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E DdPp 190 250 -60 3600.00 14.40 ddpp 210 250 -40 1600.00 6.40 Ddpp 310 250 60 3600.00 14.40 ddPp 290 250 40 1600.00 6.40 1000 1000 41.60
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote