A rectangular loop of wire with sides 0.217 and 0.443 m lies in a plane perpendi
ID: 1320842 • Letter: A
Question
A rectangular loop of wire with sides 0.217 and 0.443 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0.829 T and is directed parallel to the normal of the loop's surface. In a time of 0.265 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop.
A rectangular loop of wire with sides 0.217 and 0.443 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0.829 T and is directed parallel to the normal of the loop's surface. In a time of 0.265 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop.Explanation / Answer
induced emf is defiend as the rate of change of magnetic flux
in mathematical form,
induced emf e = NAdB/dt or NABW or NA dB/dt cos theta
where A = area
N = no. of tunrs
W = angular frequency
dB/dt = rate of change of amgnetic flux
so
emf e = 1 * 0.217 * 0.443 * 0.829/0.265
emf e = 0.3 Volts -<<<<<<<<<<<<<<<<Answer
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