A closed wire loop is in the shape of a right triangle, with sides 14cm , 14cm ,

Question

A closed wire loop is in the shape of a right triangle, with sides 14cm , 14cm , and 14 2? cm . The loop lies in the x?y plane, with the one corner at the origin and the shorter sides along the x - and y -axes. The loop carries 200mA in the clockwise direction. A uniform magnetic field of 0.75T points in the +y -direction.

Part A

Find the force on the 14cm side of the loop parallel to the x -axis. Assume the +z -direction as positive.

Part B

Find the force on the 14cm side of the loop parallel to the y -axis.

Part C

Find the force on the 14 2? cm side of the loop.

Part D

Add the forces to get the net force.

Express your answer to two significant figures and include the appropriate units.

A closed wire loop is in the shape of a right triangle, with sides 14cm , 14cm , and 14 2? cm . The loop lies in the x?y plane, with the one corner at the origin and the shorter sides along the x - and y -axes. The loop carries 200mA in the clockwise direction. A uniform magnetic field of 0.75T points in the +y -direction. Part A Find the force on the 14cm side of the loop parallel to the x -axis. Assume the +z -direction as positive. Part B Find the force on the 14cm side of the loop parallel to the y -axis. Part C Find the force on the 14 2? cm side of the loop. Part D Add the forces to get the net force. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

A)

Here ,

as Force = B X IL

Force = - 0.75 * 0.200 * 0.14

Force = -0.021 N

the force acting on this side is -0.021 N

B)

Here , as Both current and Field are parallel

Force = ZERO

c)

Now , Force = B X IL

Force = 0.75 * 0.200 * 0.14 * srqt(2) * sin(45)

Force = 0.021 N

the force acting is 0.021 N

d)

Here ,

Fnet = 0.021 + 0 - 0.021

Fnet = 0 N

Net force is Zero N

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