1)In Miami, the Earth\'s magnetic field points south and it is parallel to the s
ID: 1320685 • Letter: 1
Question
1)In Miami, the Earth's magnetic field points south and it is parallel to the surface of the earth. A cosmic beta particle ( negatively charged) enters the region vertically downward. In what direction does the particle experience force due to the Earth's magnetic field?
Down.
Into the page.
3)In a region where magnetic field is pointing east, a positively charged particle is moving west. What direction does the force acts on the charged particle?
No force due to magnetic field on that charge.
4)A high speed proton from the solar flare enters into the earth's magnetic field and starts moving in a circular path. What is the radius of that path if Earth's magnetic field is 5.0 x 10-5 T and the speed of the proton is 5.0 x105 m/s?
10-2 m.
5)A proton moving in a circular path in a cyclotron device has a kinetic energy of 1.76 x 10-12 J. If the magnetic field inside the device is 1.2 T what is the radius of the proton's orbit?
East. North. South. West. Up.Down.
2)The sketch shows the direction of magnetic field lines and the direction of the velocity of a positive charge. What is the direction of force on the charge?
Into the page.
3)In a region where magnetic field is pointing east, a positively charged particle is moving west. What direction does the force acts on the charged particle?
North. West. South.No force due to magnetic field on that charge.
4)A high speed proton from the solar flare enters into the earth's magnetic field and starts moving in a circular path. What is the radius of that path if Earth's magnetic field is 5.0 x 10-5 T and the speed of the proton is 5.0 x105 m/s?
The proton moves in a straight line. 100 m. There is not enough information.10-2 m.
5)A proton moving in a circular path in a cyclotron device has a kinetic energy of 1.76 x 10-12 J. If the magnetic field inside the device is 1.2 T what is the radius of the proton's orbit?
There is not enough information. 0.40 m 1.8 x 107 m 4.0 m 1)In Miami, the Earth's magnetic field points south and it is parallel to the surface of the earth. A cosmic beta particle ( negatively charged) enters the region vertically downward. In what direction does the particle experience force due to the Earth's magnetic field? East. North. South. West. Up. Down. 2)The sketch shows the direction of magnetic field lines and the direction of the velocity of a positive charge. What is the direction of force on the charge? To the right. To the left. Out of page. Into the page. 3)In a region where magnetic field is pointing east, a positively charged particle is moving west. What direction does the force acts on the charged particle? North. West. South. No force due to magnetic field on that charge. 4)A high speed proton from the solar flare enters into the earth's magnetic field and starts moving in a circular path. What is the radius of that path if Earth's magnetic field is 5.0 x 10^-5 T and the speed of the proton is 5.0 x10^5 m/s? The proton moves in a straight line. 100 m. There is not enough information. 10^-2 m. 5)A proton moving in a circular path in a cyclotron device has a kinetic energy of 1.76 x 10^-12 J. If the magnetic field inside the device is 1.2 T what is the radius of the proton's orbit? There is not enough information. 0.40 m 1.8 x 10^7 m 4.0 mExplanation / Answer
1. East.
2. out of the page
3. south
4. apply r = mv/qB
r = (1.67 e-27 * 5e5)/(1.6e-19 * 5e-5)
r =104.375 or 100 m
5,. apply 0.5mv^2 = 1.76 e-12
v^2 = 1.76e-12 *2/(1.67e-27)
v = 4.59 *10^7 m/s
so
r = mv/qB
r = (1.67e-27 * 4.59e 7/(1.6e-19 * 1.2)
r = 0.4 m
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