b) In which direction does the change of momentum vector point? (Take the x -axi

Question

b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)

Theta2 = 69.0° and a speed of v2 = 2.10 m/s. a) What is the magnitude of the change in momentum of the billiard ball? b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.) Theta1 = 44.0° at a speed of v1 = 3.00 m/s. It bounces off at an angle of A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of

Explanation / Answer

v1x = 3*sin44 = 2.08

v1y = -3*cos44 = -2.16

V2x = 2.1*sin69 = 1.96 m/s

v2y = 2.1*cos69 = 0.753 m/s

dPx = m*(v2x-v1x) = 0.15*(1.96-2.08) = -0.018 kg m/s

dPy = m*(v2y-v1y) = 0.15*(0.753+2.16) = 0.43695 kg m/s

dp = sqrt(dpx62 + dpy^2) = 0.437 kg m/s <-------answer

b) direction = tan^-1(dpy/dpx) = +92.4

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