Problem 20.11 A velocity selector having uniform perpendicular electric and magn

Question

Problem 20.11

A velocity selector having uniform perpendicular electric and magnetic fields is shown in the figure(Figure 1) . The electric field is provided by a 150VDC battery connected across two large parallel metal plates that are 4.50cm apart.

Part A

What must be the magnitude of the magnetic field so that charges having a velocity of 3.30km/sperpendicular to the fields will pass through undeflected?

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Part B

Show how the magnetic field should point in the region between the plates.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

3800 Character(s) remaining

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Problem 20.11

A velocity selector having uniform perpendicular electric and magnetic fields is shown in the figure(Figure 1) . The electric field is provided by a 150VDC battery connected across two large parallel metal plates that are 4.50cm apart.

Part A

What must be the magnitude of the magnetic field so that charges having a velocity of 3.30km/sperpendicular to the fields will pass through undeflected?

SubmitMy AnswersGive Up

Part B

Show how the magnetic field should point in the region between the plates.

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

3800 Character(s) remaining

SubmitMy AnswersGive Up

Explanation / Answer

Part A)

First we need the electric field between the plates

V = Ed

150 = E(.045)

E = 3333.33 V/m

Then v = E/B

3300 = 3333.33/B

B = 1.01 T

Part B)

Since the figure is not shown, I can;t tell you directly, but here is how you will figure it out. The E-field, B-field, and velocity must all be perpendicular. That means 1 in the x direction, 1 in the y direction, and 1 in the z direction.

So look at your picture and determine the direction of the E field and the velocity. (My guess is that it is going up or down). The velocity is probably to the right. Thus the B field will have to b into or out of the page. If the E field is down for a positive charge, the B field will be out of the page.

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